(1) In a chess tournament each of six players will play every other player exactly once. How many matches will be played during the tournament ?
  • 12
  • 15
  • 30
  • 36
Answer: Option B 
Explanation:
I. matches of first player with other 5 players
II. matches of second player with 4 players other than the first player
III. matches of third player with 3 players other than the first player and second player.
IV. matches of fourth player with 2 players other than the first player, second player and third player.
V. matches of fifth player with 1 player other than the first player, second player, third player and fourth player.
So total matches will be 5+4+3+2+1 = 15


(2) I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute ?

  • 25
  • 37
  • 54
  • 65


Answer: Option A

Explanation:
The required number will be such that it leaves a reminder of 1 when divided by 2, 3 or 4 and no reminder when divided by 5. Such a number is 25 among options


(3) A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
  • 8
  • 10
  • 12
  • 14

Answer: Option D

Explanation:
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5X = 70 or x = 14.



(4) A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

  • 9, 46
  • 9, 50
  • 10, 46
  • 10, 50


Answer: Option B

Explanation:
As from the question we have,
A = 3B --- (i)
c - 4 = 2(A+4) ---(ii)
Also, A + 4 = 31
or A = 31-4 = 27
Putting A = 27 in (i) we get
B = 9
Putting A = 27 in (ii) we get
C = 50



(5) Reena is twice as old as Sunita. Three years ago, she was three times as old as Sunita. How old is Reena now ?

  • 6 years
  • 12 years
  • 14 years
  • 16 years


Answer: Option B

Explanation:
Let Sunita's present age = x years
Then Reena present age = 2x years
Three years ago
(2x-3) = 3(x-3)
2x - 3 = 3x - 9
or x = 6
Reena age = 2x = 2*6 = 12 year.